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k^2+10k=-25
We move all terms to the left:
k^2+10k-(-25)=0
We add all the numbers together, and all the variables
k^2+10k+25=0
a = 1; b = 10; c = +25;
Δ = b2-4ac
Δ = 102-4·1·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$k=\frac{-b}{2a}=\frac{-10}{2}=-5$
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